Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Die | 1200 | 56 | 3 | 18.6667 |
Und | 180 | 16 | 1 | 16.0000 |
erst | 90 | 8 | 1 | 8.0000 |
sagte | 238 | 8 | 1 | 8.0000 |
Das | 483 | 22 | 3 | 7.3333 |
ob | 63 | 7 | 1 | 7.0000 |
ins | 104 | 7 | 1 | 7.0000 |
Der | 583 | 21 | 3 | 7.0000 |
nicht nur | 84 | 7 | 1 | 7.0000 |
Im | 214 | 13 | 2 | 6.5000 |
dass | 251 | 13 | 2 | 6.5000 |
Er | 190 | 13 | 2 | 6.5000 |
wo | 51 | 6 | 1 | 6.0000 |
Doch | 110 | 6 | 1 | 6.0000 |
kommt | 85 | 5 | 1 | 5.0000 |
konnte | 48 | 5 | 1 | 5.0000 |
wollte | 71 | 5 | 1 | 5.0000 |
hatten | 101 | 5 | 1 | 5.0000 |
wegen | 64 | 5 | 1 | 5.0000 |
Es | 223 | 15 | 3 | 5.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
ihren | 119 | 1 | 9 | 0.1111 |
Wochen | 52 | 1 | 9 | 0.1111 |
alle | 126 | 1 | 8 | 0.1250 |
diese | 140 | 1 | 7 | 0.1429 |
Frau | 65 | 1 | 7 | 0.1429 |
Mann | 63 | 1 | 7 | 0.1429 |
andere | 87 | 1 | 7 | 0.1429 |
seine | 225 | 2 | 13 | 0.1538 |
ihrer | 112 | 1 | 6 | 0.1667 |
Woche | 42 | 1 | 5 | 0.2000 |
Telekom | 28 | 1 | 5 | 0.2000 |
Börse | 22 | 1 | 5 | 0.2000 |
diesen | 70 | 1 | 5 | 0.2000 |
große | 62 | 1 | 5 | 0.2000 |
Bank | 41 | 1 | 5 | 0.2000 |
Fall | 38 | 1 | 5 | 0.2000 |
beiden | 63 | 1 | 5 | 0.2000 |
großen | 61 | 1 | 5 | 0.2000 |
Berliner | 121 | 2 | 9 | 0.2222 |
uns | 124 | 2 | 9 | 0.2222 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II